bash - Awk regex for a string of exact length that ends in ":" -

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i can't regex right:

awk '$6 ~ /:${14}/ {print $6}' file

i need print out 6th field if it's 15 characters long , ends ":".

here's example: oafkq7xs001224:

you need use --posix as:

awk --posix '{ if ($6 ~ /^.{14}:$/) print $6}' file

command in action

from awk manual page:

interval expressions available if either --posix or --re-interval specified on command line.


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