c++ - Perform rounding on integral type, but not fractional type -

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in following function looking expression replace isintegral<t>.

the intention when t integral type add 0.5f before static_cast implictly floors value (and obtain rounded value), when t fractional type add nothing, , static_cast can reduce precision.

t interpolate( t const & prev, t const & next, float interpolation ) {     float prevfloat = static_cast< float >( prev );     float nextfloat = static_cast< float >( next );      float result = prevfloat + ( (nextfloat-prevfloat) * interpolation );      return static_cast< t >( result + ( isintegral<t> ? 0.5f : 0.0f ); }

use std::numeric_limits<t>::is_integer (it's in <limits> header).


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