Weird value when I declare a string in C -

i want declare string hold 4 chars

char st[4]; memcpy(st,"test",4);

but when print st ... have "test" , other symbols printed after - wrong in ?

thanks lot

c strings, "test" string literal, nul-terminated, meaning last character '\0':

{'t', 'e', 's', 't', '\0'}

you need use st[5], , copy 5 characters, have room (and include) nul. is, you're not including in copy. aftewards, st looks like:

{'t', 'e', 's', 't', x, x, x ... '\0'}

when print, c keeps reading gibberish values coincidentally in memory (x'es above) until finds nul.

the best solution eliminate memcpy, , let compiler figure out size initialization:

char st[] = "test";

sizeof(st) 5.

Nine