Convert time string in XSLT -

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how convert time string like

20101115083000 +0200

to

2010-11-15 08:30:00 +0200

using xslt?

we use templates:

<xsl:template name="format-date-time">     <xsl:param name="date" select="'%y-%m-%dt%h:%m:%s%z'"/>     <xsl:value-of select="substring($date, 9, 2)"/>     <xsl:text>/</xsl:text>     <xsl:value-of select="substring($date, 6, 2)"/>     <xsl:text>/</xsl:text>     <xsl:value-of select="substring($date, 1, 4)"/>     <xsl:text> </xsl:text>     <xsl:value-of select="substring($date, 12, 2)"/>     <xsl:text>:</xsl:text>     <xsl:value-of select="substring($date, 15, 2)"/>     <xsl:text>:</xsl:text>     <xsl:value-of select="substring($date, 18, 2)"/> </xsl:template>

we call these templates this:

<xsl:call-template name="format-date-time">     <xsl:with-param name="date" select="./startdate"/> </xsl:call-template>

./startdate xml date, substring technique, think solve problem too.


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