active directory - How do I add permissions to an OU using C#? -

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i want give access permission on ou of active directory. have done part below, removes access of ou. code below:

directoryentry rootentry = new directoryentry("ldap://ou=test ou,dc=test,dc=com");  directorysearcher dsfindous = new directorysearcher(rootentry);   dsfindous.filter = "(objectclass=organizationalunit)";  dsfindous.searchscope = searchscope.subtree;  searchresult oresults = dsfindous.findone();  directoryentry myou = oresults.getdirectoryentry();   system.security.principal.identityreference newowner = new system.security.principal.ntaccount("yourdomain", "yourusername").translate(typeof(system.security.principal.securityidentifier));  activedirectoryaccessrule newrule = new activedirectoryaccessrule(newowner, activedirectoryrights.genericall, system.security.accesscontrol.accesscontroltype.deny);  myou.objectsecurity.setaccessrule(newrule); myou.commitchanges();

now problem if remove permission ad ou how can give permission again(revert permissions again). tried system.security.accesscontrol.accesscontroltype.allow newrule. there no permission ou throws exception on :

searchresult oresults = dsfindous.findone();  directoryentry myou = oresults.getdirectoryentry();

how can give rights again perticualr ou again in c#.

update:

activedirectoryaccessrule(newowner, activedirectoryrights.genericall, system.security.accesscontrol.accesscontroltype.deny);

but problem have removed generic rights, , when try search ou again won't find again. can't apply suggested logic again. can try out:). give me way, how can access ou again.

simply replace line:

activedirectoryaccessrule newrule = new activedirectoryaccessrule(newowner, activedirectoryrights.genericall, system.security.accesscontrol.accesscontroltype.deny);

with this:

activedirectoryaccessrule newrule = new activedirectoryaccessrule(newowner, activedirectoryrights.genericall, system.security.accesscontrol.accesscontroltype.allow);
  • change "deny" "allow".

p.s. : please format code lines in question appear code.


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