Filename extraction with regex -

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i need able extract filename (info.txt) line like:

07/01/2010  07:25p                 953 info.txt

i've tried using this: /d+\s+\d+\s+\d+\s+(?.?)/, doesn't seem work ... 

\d\d:\d\d\w\s+\d+\s+(.*?)$

$1 file name

the problem original regex forgets special characters :, /, , (?.?) means nothing...


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