c++ - What does *& mean in a function parameter -

if have function takes int *&, means? how can pass int or pointer int function?

function(int *& mynumber); 

whenever try pass pointer function says:

error: no matching function call 'function(int *)' note: candidate 'function(int *&)' 

it's reference pointer int. means function in question can modify pointer int itself.

you can pass pointer in, 1 complication being pointer needs l-value, not r-value, example

int myint; function(&myint); 

alone isn't sufficient , neither 0/null allowable, as:

int myint; int *myintptr = &myint; function(myintptr); 

would acceptable. when function returns it's quite possible myintptr no longer point pointing to.

int *myintptr = null; function(myintptr); 

might make sense if function expecting allocate memory when given null pointer. check documentation provided function (or read source!) see how pointer expected used.